(8-2x)^(1/2)-x=0

Solution for (8-2x)^(1/2)-x=0 equation:

(8-2x)^(1/2)-x=0

We add all the numbers together, and all the variables

(-2x+8)^(+1/2)-x=0

We add all the numbers together, and all the variables

-1x+(-2x+8)^(+1/2)=0

We multiply all the terms by the denominator


-1x*2)+(-2x+1+8)^(=0

We add all the numbers together, and all the variables

-1x*2)+(-2x+9)^(=0

We add all the numbers together, and all the variables

-2x-1x*2)+(=0

Wy multiply elements

-2x^2-2x=0

a = -2; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-2)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-2}=\frac{4}{-4}
=-1
$